I like binance cus you don't even need id and you can still trade, with like 0.1% trading fees but unfortunately has like 50 doge ($2.83 as of writing this) withdrawal fees if ur fine with that.
yes but Im too lazyFor number 2 if you want to be lazy, you could just do this:
x+y+z=0
x=y+z
2y+2z-2x=1
First 2 are just random formulas, but from those you know y+z-x=0, so you just make it y+z-x=1 so it doesn't work, but since that looks tooooo lazy, you just multiple both sides by...
For 1 E
3 logx - log(2x^2+x-2)=0
Since Y*log(X)= log(X^Y) you get
log(x^3) - log(2x^2+x-2)=0
Log(a)-Log(b)= Log(a/b) so you get
log( x^3 )
----------(divide) =0
(2x^2+x-2)
Since X^0=1 Log(1)=0 Sooooo
( x^3)/(2x^2+x-2) =1
So they equal and we get
(...
Just trying my best here, please dont yeet me, Ill add more when I solve them starting from the easier ones(If I solve them):
Starting off 1C the easiest question
1 .C) 2x^2 * (x-3)^2 * (3x+4)=0
If any one of the three (2x^2), (x-3)^2, (3x+4) is 0, the entire equation is 0 cus...
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