Free Gfx for Small Server Owners

[KnightDeluxe12]

Hello guys, This contest will help to improve my gfx skills.So this is the mechanics.

I have two 3 digit code numbers.So as a contestant you will be guest what is that code.Each digit must be more than 1 and less than 3 or let say 111-333.So this is the rule,The digit must not be the same to each other like 223 244 etc.Only 3 code for each contestant.

Note: This contest is for small server owners only

2 lucky winners will be announce on Tuesday.

 

[Helloimrex]

This isn't possible,

Each digit must be more than 1 and less than 3.

So the number has to be 222, literally no other number works.

The digit must not be the same to each other like 223 244 etc.

Well, blame it on the night then I guess because no numbers work at all.

Even if the grammar is corrected to say a number between 1 and 3 including 1 and 3, there are still very limited possibilities. The first criterion leaves,
111, 112, 113, 121, 122, 123, 131, 132, 133, 211, 212, 213, 221, 222, 223, 231, 232, 233, 311, 312, 313, 321, 322, 333

With the second criterion only six of the numbers work:
111, 112, 113, 121, 122, 123, 131, 132, 133, 211, 212, 213, 221, 222, 223, 231, 232, 233, 311, 312, 313, 321, 322, 333

So with 3 guesses you have a 50% chance of winning...

Oh, you have 2 code numbers? So two of these work? Well then the chance of picking right is a little bit better than 50%.

It's 1-[(4/6)(3/5)(2/4)]=80%

For now I guess I'll just guess the 3 numbers the other guy didn't.

So my guesses are 123, 213 and 231 and I should have an 80% chance of winning.